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信息安全工程師每日一練試題內(nèi)容（2022/1/19）

試題1： A方有一對(duì)密鑰（KApub，KApri），B方有一對(duì)密匙（KBpub，KBpri），A方給B方發(fā)送信息M，對(duì)信息M加密為：M ‘ = KBpub（KApri（M））。B方收到密文，正確的解決方案是（）
A. KBpub（KApri（M ‘ ））
B. KBpub（KApub（M ‘ ））
C. KApub（KBpri（M ‘ ））
D. KBpri（KApri（M ‘ ））
試題解析與討論：m.xiexiliangjiufa.com/st/3272224096.html
試題參考答案：C

試題2： Trust is typically interpreted as a subjective belief in the reliability， honesty and  security  of an entity on which we depend （ ）our welfare .In online environments we depend on a wide spectrun of things , ranging from computer hardware,software and data to people and organizations. A security solution always assumes certain entities function according to specific policies.To trust is precisely to make this sort of assumptions , hence , a trusted entity is the same as an entity that is assumed to function according to  policy . A consequence of this is that a trust component of a system must work correctly in order   for the security of that system to hold, meaning that when a trusted（  ）fails , then the sytems and applications that depend on it can（  ）be considered secure.An often cited articulation of this principle is:＂ a trusted system or component is one that can break your security policy” ( which happens when the trust system fails ). The same applies to a trusted party such as a service provider ( SP for short )that is , it must operate according to the agreed or assumed   policy in order to ensure the expected level of securty and quality of services . A paradoxical   conclusion to be drawn from this analysis is that security assurance may decrease when increasing the number of trusted components and parties that a service infrastructure depends on . This is because the security of an infrastructure consisting of many.
Trusted components typically follows the principle of the weakest link , that is ,in many situations the the overall security can only be as strong as the least reliable or least secure of all the trusted components. We cannot avoid using trusted security components,but the fewer the better. This is important to understand when designing the  identity management architectures,that is, fewer the trusted parties in an identity management model , stronger the security that can be achieved by it.
The transfer of the social constructs of identity and trust into digital and computational concepts helps in designing and implementing large scale online markets and communities,and also plays an important role in the converging mobile and Internet environments.Identity management (denoted Idm hereafter ) is about recognizing and verifying the correctness of identitied in online environment .Trust management becomes a component of （  ）whenever different parties rely on each other for identity provision and authentication . IdM and Trust management therefore depend on each other in complex ways because the correctness of the identity itself must be trusted for the quality and reliability of the corresponding entity to be trusted.IdM is also an essential concept when defining  authorisation policies in personalised services.
Establishing trust always has a cost, so that having  complex trust requirement typically leads to high overhead in establishing the required trust. To reduce costs there will be incentives for stakeholders to “cut corners”regarding trust requirements ,which could lead to inadequate security . The challenge is to design IdM systems with relatively simple trust requirements.Cryptographic mechanisms are often a core component of IdM solutions,for example,for entity and data authentication.With cryptography,it is often possible to propagate trust from where it initially exists to where it is needed .The establishment of initial（  ）usually takes place in the physical world,and the subsequent propagation of trust happens online,often in an automated manner.
（71）A.with
B. on
C. of
D. for
（72）A.entity
B.person
C.component
D.thing
（73）A. No longer
B. never
C. always
D.often
（74）A. SP
B. IdM
C.Internet
D.entity
（75）A.trust
B.cost
C.IdM
D. solution
試題解析與討論：m.xiexiliangjiufa.com/st/389944612.html
試題參考答案：D、C、A、B、A

試題3： IP地址欺騙的發(fā)生過(guò)程，下列順序正確的是（）。①確定要攻擊的主機(jī)A；②發(fā)現(xiàn)和他有信任關(guān)系的主機(jī)B；③猜測(cè)序列號(hào)；④成功連接，留下后面；⑤將B利用某種方法攻擊癱瘓。
A.①②⑤③④
B.①②③④⑤
C.①②④③⑤
D.②①⑤③④
試題解析與討論：m.xiexiliangjiufa.com/st/3273328170.html
試題參考答案：A

試題4：

以下關(guān)于隧道技術(shù)說(shuō)法不正確的是（）
A、隧道技術(shù)可以用來(lái)解決TCP/IP協(xié)議的某種安全威脅問(wèn)題
B、隧道技術(shù)的本質(zhì)是用一種協(xié)議來(lái)傳輸另外一種協(xié)議
C、IPSec協(xié)議中不會(huì)使用隧道技術(shù)
D、虛擬專用網(wǎng)中可以采用隧道技術(shù)

試題解析與討論：m.xiexiliangjiufa.com/st/2850118239.html
試題參考答案：C

試題5： 無(wú)線傳感器網(wǎng)絡(luò)容易受到各種惡意攻擊，以下關(guān)于其防御手段說(shuō)法錯(cuò)誤的是（）。
A.采用干擾區(qū)內(nèi)節(jié)點(diǎn)切換頻率的方式抵御干擾
B.通過(guò)向獨(dú)立多路徑發(fā)送驗(yàn)證數(shù)據(jù)來(lái)發(fā)現(xiàn)異常節(jié)點(diǎn)
C.利用中心節(jié)點(diǎn)監(jiān)視網(wǎng)絡(luò)中其它所有節(jié)點(diǎn)來(lái)發(fā)現(xiàn)惡意節(jié)點(diǎn)
D.利用安全并具有彈性的時(shí)間同步協(xié)議對(duì)抗外部攻擊和被俘獲節(jié)點(diǎn)的影響
試題解析與討論：m.xiexiliangjiufa.com/st/3274326177.html
試題參考答案：C

試題6： 設(shè)在RSA的公鑰密碼體制中，用于為（e，n）=（7,55），則私鑰d=（）。
A. 8
B. 13
C. 23
D. 37
試題解析與討論：m.xiexiliangjiufa.com/st/327521419.html
試題參考答案：C

試題7： X.509數(shù)字證書的內(nèi)容不包括（）。
A.版本號(hào)
B.簽名算法標(biāo)識(shí)
C.加密算法標(biāo)識(shí)
D.主體的公開(kāi)密鑰信息
試題解析與討論：m.xiexiliangjiufa.com/st/327479174.html
試題參考答案：C

試題8： 計(jì)算機(jī)系統(tǒng)的安全級(jí)別分為四級(jí)：D、C（C1、C2）、B（B1、B2、B3）和A。其中被稱為選擇保護(hù)級(jí)的是（）
A. C1
B. C2
C. B1
D. B2
試題解析與討論：m.xiexiliangjiufa.com/st/3273210010.html
試題參考答案：A

試題9： 文件加密就是將重要的文件以密文形式存儲(chǔ)在媒介上，對(duì)文件進(jìn)行加密是一種有效的數(shù)據(jù)加密存儲(chǔ)技術(shù)?；赪indows系統(tǒng)的是（  ）。
A. AFS
B. TCFS
C. CFS
D. EFS
試題解析與討論：m.xiexiliangjiufa.com/st/4110015512.html
試題參考答案：D

試題10： （  ）攻擊是指借助于客戶機(jī)/服務(wù)器技術(shù),將多個(gè)計(jì)算機(jī)聯(lián)合起來(lái)作為攻擊平臺(tái)，對(duì)一個(gè)或多個(gè)目標(biāo)發(fā)動(dòng)DoS攻擊，從而成倍地提高拒絕服務(wù)攻擊的威力。
A.緩沖區(qū)溢出
B.分布式拒絕服務(wù)
C.拒絕服務(wù)
D. 口令
試題解析與討論：m.xiexiliangjiufa.com/st/4114823197.html
試題參考答案：B