試題1

（）不屬于按尋址方式劃分的一類存儲(chǔ)器。
A．隨機(jī)存儲(chǔ)器
B．順序存儲(chǔ)器
C．相聯(lián)存儲(chǔ)器
D．直接存儲(chǔ)器

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試題2

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試題3

在進(jìn)行金融業(yè)務(wù)系統(tǒng)的網(wǎng)絡(luò)設(shè)計(jì)時(shí)，應(yīng)該優(yōu)先考慮（1）原則。在進(jìn)行企業(yè)網(wǎng)絡(luò)的需求分析時(shí)，應(yīng)該首先進(jìn)行（2） 。
（1）A、先進(jìn)性
B、開(kāi)放性
C、經(jīng)濟(jì)性
D、高可用性
（2）A、企業(yè)應(yīng)用分析
B、網(wǎng)絡(luò)流量分析
C、外部通信環(huán)境調(diào)研
D、數(shù)據(jù)流向圖分析

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試題4

分配給某校園網(wǎng)的地址塊是202.105.192.0/18，該校園網(wǎng)包含 （ ） 個(gè)C類網(wǎng)絡(luò)。
A、6
B、14
C、30
D、62

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試題5

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試題6

計(jì)算機(jī)指令一般包括操作碼和地址碼兩部分，為分析執(zhí)行一條指令，其  （ ）  。
A、操作碼應(yīng)存入指令寄存器（IR），地址碼應(yīng)存入程序計(jì)數(shù)器（PC）
B、操作碼應(yīng)存入程序計(jì)數(shù)器（PC），地址碼應(yīng)存入指令寄存器（IR）
C、操作碼和地址碼都應(yīng)存入指令寄存器（IR）
D、操作碼和地址碼都應(yīng)存入程序計(jì)數(shù)器（PC）

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試題7

Software entities are more complex for their size than perhaps any other humanconstruct, because no two parts are alike （at least above the statement level）. If they are, wemake the two similar parts into one, a（ 71 ）, open or closeD． In this respect software systemsdiffer profoundly from computers, buildings, or automobiles, where repeated elements abound．
Digital computers . are themselves more complex than most things people build;they have very large numbers of states This makes conceiving, describing, and testing them harD． Software systems have orders of magnitude more（ 72 ）than computers do
Likewise, a scaling-up of a software entity is not m erely a repetition of the same elementsm larger size; it is necessarily an mcrease in the number of different elements. In most cases, the elements interact with each other in some（ 73 ）fashion: and the complexity of the wholencreases much more than linearly.
The complexity of software is a（an）（ 74 ）property, not an accidental one Hencedescriptions of a software entity that abstract away its complexity often abstract away its essence.Mathematics and the physical sciences made great strides for threecenturies by constructingsimplified models of complex phenomena, deriving properties fiom the models, and verifyingthose properties experimentally. This worked becausethe complexities（ 75 ） in the modelswere not the .essential properties of the phenomena: It does not work when the complexities are the essence.
Many of the classical problems of developing software products derive from this essential complexi and its nonlinear uicreases with size. Not only .technical problems but management problems as well come from the coin plexity.
A． task
B．job
C．subroitune
D．Program
A．states
B．parts
C．conditions
D．Expressions
A．linear
B. nonlinear
C．Parallel
D．Addititive
A. surface
B． Outside
C．exterior
D．Essential
A． fixed
B． Included
C．ignored
D．stabilized

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試題8

下圖為一確定有限自動(dòng)機(jī)(DFA)的狀態(tài)轉(zhuǎn)換圖，與該自動(dòng)機(jī)等價(jià)的正規(guī)表達(dá)式是（1），圖中的（2）是可以合并的狀態(tài)?

（1）A、(a|b)*bb(a*b*)*
B、(a|b)*bba*|b*
C、(a*b*)bb(a|b)*
D、(a|b)*bb(a*|b*)*
（2）A、0和1
B、2和3
C、1和2
D、0和3

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試題9

軟件能力成熟度模型（CMM）的第 4 級(jí)（已管理級(jí)）的核心是（ ）
A、建立基本的項(xiàng)目管理和實(shí)踐來(lái)跟蹤項(xiàng)目費(fèi)用、進(jìn)度和功能特性
B、組織具有標(biāo)準(zhǔn)軟件過(guò)程
C、對(duì)軟件過(guò)程和產(chǎn)品都有定量的理解和控制
D、先進(jìn)的新思想和新技術(shù)促進(jìn)過(guò)程不斷改進(jìn)

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試題10

下面關(guān)于校驗(yàn)方法的敘述，  （ ）  是正確的。
A、采用奇偶校驗(yàn)可檢測(cè)數(shù)據(jù)傳輸過(guò)程中出現(xiàn)一位數(shù)據(jù)錯(cuò)誤的位置并加以糾正
B、采用海明校驗(yàn)可檢測(cè)數(shù)據(jù)傳輸過(guò)程中出現(xiàn)一位數(shù)據(jù)錯(cuò)誤的位置并加以糾正
C、采用海明校驗(yàn)，校驗(yàn)碼的長(zhǎng)度和位置可隨機(jī)設(shè)定
D、采用 CRC 校驗(yàn)，需要將校驗(yàn)碼分散開(kāi)并插入數(shù)據(jù)的指定位置中

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