試題1

在IE瀏覽器中，安全級別最高的區(qū)域設(shè)置是（）。
A．Internet
B．本地Intranet
C．可信站點
D．受限站點

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試題2

設(shè)一個包含n個頂點、e條弧的簡單有向圖采用鄰接矩陣存儲結(jié)構(gòu)（即矩陣元素A[i][j]團等于1或0，分別表示頂點i與頂點j之間有弧或無?。?則該矩陣購非零元素數(shù)目為（ ）。

A. e
B.2e
C.n-e
D．n+e

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試題3

分布式數(shù)據(jù)庫系統(tǒng)中， ( )是指用戶無需知道數(shù)據(jù)存放的物理位置。
A．分片透明
B．復制透明
C．邏輯透明
D．位置透明

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試題4

why have formal documents 
first, writing the decisions down is essential.Only when one writes do the gaps appear and the    (1)    protrude(突出).The act of writing turns out to require hundreds of mini-decisions.and it is the existence of these that distinguishes clear.exact policies from fuzzy ones.
Second.the documents will communicate the decisions to others. The manager will be continually amazed that poliaes he took for common knowledge are totally unknown by some member of his team . Since his fundamentaljob is to keep everybody going in the  (2)directon. his chief daily task will be communication, not decision-making,and his documents will immensely   (3)   this load.
Finally.a manager,s documents give him a data base and checklist. By reviewing them (4)he sees where he is. and he sees what changes of emphasis or shifts in direction are needed.
The task of the manager is to develop a plan and then to realize it. But only the written plan is precise and communicable. Such a plan consists of documents on what.when. how much.where.and who.This small set of critical documents  (5)  much of the manager.s   work.if their comprehensive and critical nature is recognized in the beginning. the manager can approach them as friendly tools rather than annoying busywork. He will set his direction much more crisply and quickly by doing so.
（1）A.inconsistencies
B.consistencies
C.steadiness
D.adaptability
（2）A.other
B.different
C.another
D.same
（3）A.extend
B.broaden
C.lighten
D.release
（4）A.periodically
B.occasionally
C.infrequently
D.rarely
（5）A.decides
B.encapsulates
C.realizes
D.recognizes

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試題5

計算機感染特洛伊木馬后的典型現(xiàn)象是 （ ） 。
A、程序異常退出
B、有未知程序試圖建立網(wǎng)絡(luò)連接
C、郵箱被垃圾郵件填滿
D、Windows 系統(tǒng)黑屏

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試題6

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試題7

現(xiàn)要對n個實數(shù)(僅包含正實數(shù)和負實數(shù))組成的數(shù)組A進行重新排列，使得其中所有的負實數(shù)都位于正實數(shù)之前。求解該問題的算法的偽代碼如下所示，則該算法的時間和空間復雜度分別為（）。

i=0; j=n-1;

while i＜jdo

while A[i]＜0 do

i=i+1;

while A[j]＞0 do

j=j-1;

if i＜j do

交換A[i]和A[j];

A. A
B. B
C. C
D. D

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試題8

將高級語言程序翻譯為機器語言程序的過程中，常引入中間代碼，其好處是（）
A、有利于進行反編譯處理
B、有利于進行與機器無關(guān)的優(yōu)化處理
C、盡早發(fā)現(xiàn)語法錯誤
D、可以簡化語法和語義分析

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試題9

函數(shù)t()、f()的定義如下所示，若調(diào)用函數(shù)t時傳遞給x的值為5，并且調(diào)用函數(shù)F()時，第一個參數(shù)采用傳值（call by value）方式，第二個參數(shù)采用傳引用(call by reference)方式，則函數(shù)t的返回值為( ) 。

A 33
B. 22
C. 11
D.負數(shù)

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試題10

繼承是父類和子類之間共享數(shù)據(jù)和方法的機制。以下關(guān)于繼承的敘述中，不正確的是（1）。有關(guān)下圖中doIt（）方法的敘述中，正確的是（2）。



（1）A．一個父類可以有多個子類，這些子類都是父類的特例
B．父類描述了這些子類的公共屬性和操作
C．子類可以繼承它的父類(或祖先類)中的屬性和操作而不必自己定義
D．子類中可以定義自己的新操作而不能定義和父類同名的操作
（2）A．dolt()必須由Thing3實現(xiàn)，同時可能用Thing4實現(xiàn)
B．dolt()必須由Thing5實現(xiàn)
C．dolt()必須由Thing2、Thing3、Thing4和Thing5實現(xiàn)
D．dolt()已經(jīng)由Thing1實現(xiàn)，因此無須其他類實現(xiàn)

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