試題1

某網(wǎng)站向 CA 申請(qǐng)了數(shù)字證書(shū)，用戶通過(guò)（ ）來(lái)驗(yàn)證網(wǎng)站的真?zhèn)?br />A、CA 的簽名
B、證書(shū)中的公鑰
C、網(wǎng)站的私鑰
D、用戶的公鑰

查看答案

試題2

there is nothing in this world constant but inconstancy.-SWIFT
Project after project designs a set of algorithms and then plunges intoconstruction of customer-deliverable software on a schedule that demands delivery of the first thing built.
In most projects, the first system built is (1) usable. It may be too slow, too big , awkward to use, or all three. There is no (2 ) but to start again, smarting but smarter and build a redesigned version in which these problems are solved. The discard and (3) may be done in one lump, or it may be done piece-by-piece. But all large-system experience shows that it will be done. Where a new system concept or new technology is used, one has to build a syste m to throw away, for even the best
planning is not so omniscient (全知的) as to get it fight the first time.
the management question, therefore, is not whether to build a pilot system and throw it away. You will do that. The only question is whether to plan in advance to build a (4).or to promise to deliver the throwaway to customers. Seen this way, the answer is much clearer. Delivering that throwaway to customers buys time, but it does so only at the (5) of agony (極大痛苦) for the user, distraction for the builders while they do the redesign, and a bad..reputation for the product that the best redesign will find hard to live down.
Henceplanto throw one away; you will,anyhow.
The management question, therefore, is not whether to build a pilot system and throw it away. You will do that. The only question is whether to plan in advance to build a throwaway, or to promise to deliver the throwaway to customers. Seen this way, the answer is much clearer. Delivering that throwaway to customers buys time, but it does so only at the cost of agony for the user, distraction for the builders while they do the redesign, and a bad reputation for the product that the best redesign will find hard to live down.
(1)A.almost
B.often
C.usually
D.barely
(2)A.alternative
B.need
C.possibility
D.solution
(3)A.design
B.redesign
C.plan
D.build
(4) A.throwaway
B.system
C.software
D.product
(5) A.worth
B. value
C. cost
D. invaluable

查看答案

試題3

隨著網(wǎng)站知名度不斷提高，網(wǎng)站訪問(wèn)量逐漸上升，網(wǎng)站負(fù)荷越來(lái)越重，針對(duì)此問(wèn)題，一方面可通過(guò)升級(jí)網(wǎng)站服務(wù)器的軟硬件，另一方面可以通過(guò)集群技術(shù)，如DNS負(fù)載均衡來(lái)解決。在Windows的DNS服務(wù)器中通過(guò)（）操作可以確保域名解析并實(shí)現(xiàn)負(fù)載均衡。
A．啟用循環(huán)，啟動(dòng)轉(zhuǎn)發(fā)器指向每個(gè)Web服務(wù)器
B．禁止循環(huán)，啟動(dòng)轉(zhuǎn)發(fā)器指向每個(gè)Web服務(wù)器
C．禁止循環(huán)，添加每個(gè)Web服務(wù)器的主機(jī)記錄
D．啟用循環(huán)，添加每個(gè)Web服務(wù)器的主機(jī)記錄

查看答案

試題4

UML中關(guān)聯(lián)是一個(gè)結(jié)構(gòu)關(guān)系，描述了一組鏈。兩個(gè)類(lèi)之間（40）關(guān)聯(lián)。
A．不能有多個(gè)
B．可以有多個(gè)由不同角色標(biāo)識(shí)的
C．可以有任意多個(gè)
D．的多個(gè)關(guān)聯(lián)必須聚合成一個(gè)

查看答案

試題5

A. A
B. B
C. C
D. D

查看答案

試題6

給定關(guān)系模式R(U,F)，U={A,B,C,D,E,H}，函數(shù)依賴(lài)集F={A→B,A→C,C→D,AE→H}。關(guān)系模式R的候選關(guān)鍵字為（）。
A．AC
B．AB
C．AE
D．DE

查看答案

試題7

若采用鄰接矩陣來(lái)存儲(chǔ)簡(jiǎn)單有向圖，則其某一個(gè)頂點(diǎn)i的入度等于該矩陣（ ）。
A、第i行中值為1的元素個(gè)數(shù) 
B、所有值為1的元素總數(shù) 
C、第i行及第i列中值為1的元素總個(gè)數(shù) 
D、第i列中值為1的元素個(gè)數(shù) 

查看答案

試題8

查看答案

試題9

某程序根據(jù)輸入的三條線段長(zhǎng)度，判斷這三條線段能否構(gòu)成三角形。以下試用例中，  （ ）  兩個(gè)用例屬于同一個(gè)等價(jià)類(lèi)。
①6、7、13；        ②4、7、10；        ③9、20、35；
④9、11、21；        ⑤5、5、4；        ⑥4、4、4。
A、①②
B、③④
C、⑤⑥
D、①④

查看答案

試題10

Cache 用于存放主存數(shù)據(jù)的部分拷貝，主存單元地址與 Cache 單元地址之間的轉(zhuǎn)換工作由  （ ）  完成。
A、硬件
B、軟件
C、用戶
D、程序員

查看答案