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軟件設(shè)計(jì)師每日一練試題(2025/5/22)

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軟件設(shè)計(jì)師每日一練試題內(nèi)容(2025/5/22)

  • 試題1

    某哈希表(散列表)的長度為 N,設(shè)散列函數(shù)為 H(Key)=Keymodp ,采用 線性探測法解決沖突。以下關(guān)于 P 值的敘述中,正確是()
    A.P 的值一般為不大于 n 且最接近 n 的質(zhì)數(shù)
    B.P 的值一般為大于 n 的任意整數(shù)
    C.P 的值必須為小于 n 的合數(shù)
    D.P 的值必須等于 n

    查看答案

    試題參考答案:A

    試題解析與討論:m.xiexiliangjiufa.com/exam/ExamDay.aspx?t1=4&day=2025/5/22

  • 試題2

    若視頻圖像每幀的數(shù)據(jù)量為 6.4MB,幀速率為 30 幀/秒,則顯示 10 秒的視頻信息,其原始數(shù)據(jù)量為  ( )  MB。
    A、64
    B、192
    C、640
    D、1920

    查看答案

    試題參考答案:D

    試題解析與討論:m.xiexiliangjiufa.com/exam/ExamDay.aspx?t1=4&day=2025/5/22

  • 試題3

    視覺上的顏色可用亮度、色調(diào)和飽和度3個(gè)特征來描述。其中飽和度是指顏色的() 。
    A.種數(shù)
    B.純度
    C.感覺
    D.存儲(chǔ)量

    查看答案

    試題參考答案:B

    試題解析與討論:m.xiexiliangjiufa.com/exam/ExamDay.aspx?t1=4&day=2025/5/22

  • 試題4

    PC 機(jī)處理的音頻信號主要是人耳能聽得到的音頻信號, 它的頻率范圍是 ( )  。
    A、300Hz~3400Hz
    B、20Hz~20KHz
    C、10Hz~20KHz
    D、20Hz~44KHz

    查看答案

    試題參考答案:B

    試題解析與討論:m.xiexiliangjiufa.com/exam/ExamDay.aspx?t1=4&day=2025/5/22

  • 試題5

    在基于 Web 的電子商務(wù)應(yīng)用中, 訪問存儲(chǔ)于數(shù)據(jù)庫中的業(yè)務(wù)對象的常用方式之一是( ) 。
    A. JDBC
    B. XML
    C. CGI
    D. COM

    查看答案

    試題參考答案:A

    試題解析與討論:m.xiexiliangjiufa.com/exam/ExamDay.aspx?t1=4&day=2025/5/22

  • 試題6

    裝飾器(Decorator)模式用于();外觀(Facade)模式用于()。
    ①將一個(gè)對象加以包裝以給客戶提供其希望的另外一個(gè)接口
    ②將一個(gè)對象加以包裝以提供一些額外的行為
    ③將一個(gè)對象加以包裝以控制對這個(gè)對象的訪問
    ④將一系列對象加以包裝以簡化其接口
    (1)、A.①
    B.②
    C.③
    D.④
    (2)、A.①
    B.②
    C.③
    D.④

    查看答案

    試題參考答案:B、D

    試題解析與討論:m.xiexiliangjiufa.com/exam/ExamDay.aspx?t1=4&day=2025/5/22

  • 試題7

    集合A={d.b.c}上的二元關(guān)系R為:R={<a,a>,<c,c>,<a,b>)},則二元關(guān)系R是( )。
    A、自反的 
    B、反自反的 
    C、對稱的 
    D、傳遞的 

    查看答案

    試題參考答案:D

    試題解析與討論:m.xiexiliangjiufa.com/exam/ExamDay.aspx?t1=4&day=2025/5/22

  • 試題8

    拉斯維加斯(Las Vegas)算法是一種常用的( )算法。
    A、確定性 
    B、近似 
    C、概率 
    D、加密 

    查看答案

    試題參考答案:C

    試題解析與討論:m.xiexiliangjiufa.com/exam/ExamDay.aspx?t1=4&day=2025/5/22

  • 試題9

    The project workbook is not so much a separate document as it is a structure imposed on the documents that the project will be producing anyway.
    All the documents of the project need to be part of this ( ). This includes objectives ,external specifications , interface specifications , technical standards , internal specifications and administrative memoranda(備忘錄).
    Technical prose is almost immortal. If one examines the genealogy ( Ff ) of a customer manual for a piece of hardware or software , one can trace not only the ideas , but also many of the very sentences and paragraphs back to the first (?。?proposing the product or explaining the first design. For the technical writer, the paste-pot is as mighty as the pen.
    Since this is so, and since tomorrow&#39;s product-quality manuals will grow from today&rsquo;s memos, it is very important to get the structure of the documentation right. The early design of the project (?。?ensures that the documentation structure itself is crafted, not haphazard. Moreover, the establishment of a structure molds later writing into segments that fit into that structure.
    The second reason for the project workbook is control of the distribution of (請作答此空). The problem is not to restrict information, but to ensure that relevant information gets to all the people who need it.
    The first step is to number all memoranda, so that ordered lists of titles are available and h worker can see if he has what he wants. The organization of the workbook goes well beyond this to establish a tree-structure of memoranda. The ( ) allows distribution lists to be maintained by subtree, if that is desirable.
    A.product
    B.manual
    C.document
    D.information

    查看答案

    試題參考答案:D

    試題解析與討論:m.xiexiliangjiufa.com/exam/ExamDay.aspx?t1=4&day=2025/5/22

  • 試題10

    表達(dá)式“X = A + B × (C - D)/E”的后綴表示形式可以為 ( ) (運(yùn)算符優(yōu)先級相同時(shí),遵循左結(jié)合的原則)。
    A、XAB + CDE/-×=
    B、XA+BC-DE/×=
    C、XABCD-×E/+=
    D、XABCDE+×-/=

    查看答案

    試題參考答案:C

    試題解析與討論:m.xiexiliangjiufa.com/exam/ExamDay.aspx?t1=4&day=2025/5/22

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